已知函数f(x)=,(k,b∈N*),满足f(2)=2,f(3)>2. (1)求k,b的值; (2)若各项为正的数列{an}的前n项和为Sn,且有4Sn?f(-)=-1,设bn=a2n,求数列{n?bn}的前n项和Tn; (3)在(2)的条件下,证明:ln(1+bn)<bn. |
与“已知函数f(x)=x2kx-b,(k,b∈N*),满足f(2)=2,f(3)>2.(1)求k,b的值;(2)若各项为正的数列{an}的前n项和为Sn,且有4Sn•f(-1an)=-1,设bn=a2n,求数列{n•bn}的前n项和Tn;(3”考查相似的试题有: